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Jerjer3864
05.05.2020 •
Mathematics
Patty made a banner that has an area of 36 square inches,. The length and width of the banner are whole numbers. The length is 4 times greater than the width. What are the dimensions of the banner?
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Ответ:
width= 3 inches; length= 12 inches.
Step-by-step explanation:
From the question, the length is 4 times greater than the width.
Let the width of the banner be represented by y.
Since the length is 4 times greater than the width. It will be denoted as:
Length= 4 × y = 4y
Since area= length×width
4y × y = 36
4y^2 = 36
Divide both side by 4
y^2 = 36/4
y^2 = 9
We have to find the square root of 9
y= √9
y = 3
The width is 3 inches.
The length will be: (3×4) = 12 units.
Ответ:
The length of the banner is 12 inches while the width of the banner is 3 inches
Step-by-step explanation:
Here we have the area of the rectangular banner = 36 in²
Formula for the area of the banner is Length, L × Width, W
We are told the length is 4 times greater than the width.
That is, L = 4·W
Therefore, the area of the banner = L × W = 4·W × W = 4·W² = 36 in²
∴ W = √(36/4) = 3 inches
L = 4·W = 4 × 3 inches = 12 inches
Therefore, the dimensions of the banner are
Length of banner = 12 inches
Width of banner = 3 inches.
Ответ:
hi what's up
Step-by-step explanation:
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