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eme05
26.10.2019 •
Mathematics
Peter has money in two savings accounts. one rate is 6% and the other is 14%. if he has $900 more in the 14% account and the total interest is $221, how much is invested in each savings account?
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Ответ:
Step-by-step explanation:
Let x represent the amount Peter invested at 14%. Then (x-900) is the amount he invested at 6%. His total interest earned is ...
0.14x + 0.06(x -900) = 221
0.20x = 275 . . . . . . . . . . . . . . . . add 54, simplify
x = 1375 . . . . . . . . . . . . . . . . . . . .divide by 0.2; amount invested at 14%
(x-900) = 475 . . . . . . . . . . . . . . . amount invested at 6%
Peter invested $475 in the 6% account and $1375 in the 14% account.
Ответ:
Not possible.
Step-by-step explanation:
250 = 2 * 5 * 5 * 5
From this you write the square root as 5 * √10 so you would have to use a calculator to get any further.