Plea ! 40 points to whoever answers righ

I think this reads

in which case we would have

One is  {a=6, b=2, c=1, d=-3}

Step-by-step explanation:

If we want both functions to be equal, we need the terms to be equal one to one. This is, those term with x must be equal, and the independent term must also be equal. Lets start with the terms that has x.

In f(x) we have simply x and in g(x) we have cx. We need than x to be equal to cx:

x = cx

Here we have two possibilities:

c=1 --> x = x*1 ---> x = x

c=0 --> 0 = 0 ---> x = 0x = 0=0

Then we need the independent terms to be equal:

a/b = -d

Here we have infinite combinations. For example, we could have a=6, b=2 and d=-3, so

a/b = 6/2 = 3

-d = -(-3) = 3

So, for the set {a=6, b=2, c=1, d=-3} we have

f(x)= x + a/b = x + 6/2 = x + 3

g(x) = 1*x - (-3) = x + 3

so, f(x)=g(x)=x+3

You can try other combinations changing a, b and d, or putting c=0.

I hope it is understandable.