PLEASE HELP HEHE A bag contains 3 red balls, 8 blue balls and 11 white balls. What is the probability of drawing two balls after replacing the first ball; first is red and then a white ball? Round to the nearest tenth and include a percent sign

0.1

Step-by-step explanation:

Probability = expected outcome/total outcome

If a bag contains 3 red balls, 8 blue balls and 11 white balls, then the total outcome will be;

Total outcome = 3 + 8 + 11 = 22 balls

Since we are drawing two balls with replacement;

Probability of drawing red ball = number of red/total outcome = 3/22

Probability of drawing white ball = number of while/total outcome = 11/22 = 1/2

Probability of drawing red first and then white = 3/22 * 1/2

Probability of drawing red first and then white  = 3/44

To the nearest tenth, 3/44= 0.1

In percent = 6.8%

1/4 gallon= 2/3Bin From the problem.So multiply both sides by three to get rid of the 3 in the 2/3 Bin. (3/4=2Bin) Then divide by two to cancel out the 2Bin so there's your answer 3/8Gallons in a Bin. 3/8=Bin I'm essentially dividing 1/4 by 2/3