Please help i can’t do this

A = -3, B = 1, and C = 19 OR A = 3, B= -1, C = -19 (look at the explaination)

Step-by-step explanation:

You will need to expand the equation given to you.

y-7 = 3(x+4)

y-7=3x+12

y- 7 + 7 = 3x + 12 +7

y = 3x + 19

-3x + y = 19

Therefore, A = -3, B = 1, and C = 19

But, you can also write it as:

y = 3x + 19

3x - y = -19

A = 3, B= -1, C = -19

So, I don't know what your teacher wants but both answers should be right.

0.5 < x < 3

or (0.5, 3)

Step-by-step explanation:

-16t² + 56t + 2 = 26

Subtract both sides by 26

-16t² + 56t + 2 = 26

                 -26   -26

-16t² + 56t - 24 = 0

Divide both sides by -8 to simplify

(-16t² + 56t - 24)/8 = 0/8

2t² - 7t + 3 = 0

Factor

(x - 3)(2x - 1) = 0

Do this to find the x's

x - 3 = 0

 + 3  +3

x = 3

2x - 1 = 0

    + 1  + 1

2x = 1

2x/2 = 1/2

x = 0.5

0.5 < x < 3

This means the intervals will have to be between 0.5 and 3 seconds