PLEASE HELP I REALLY DONT UNDERSTAND IT :( WILL MARK BRAINLIEST FOR CORRECT AND IN-DEPTH ANSWERS :)
Solve the following Quadratic Equations, then sketch.
Steps
1) set y=0 (This ensures our x's will be x-intercepts)
2) Factor the Quadratic Equation into 2 parentheses, ( )( )
3) Interpret factors to get x-intercepts
4) Sketch the parabola

1) y=x^2+2x-15 2) y=x^2+5x+6

3)y=x^2-6x-40 4) y=x^2-8x+12

Step-by-step explanation:

1) x² + 2x - 15 = 0

<=> x² - 3x + 5x - 15 =0

<=> (x+5)(x - 3) = 0

<=> x = -5 or x = 3

2) x² + 5x + 6 =0

<=> x² + 2x + 3x + 6 = 0

<=> (x+3)(x+2) = 0

=> x = -3 or x = -2

3) x² - 6x - 40 = 0

<=> x² - 10x + 4x -40 = 0

<=> (x+4)(x-10) = 0

<=> x = -4 or x =10

4) x² - 8x + 12 =0

<=> x² -2x -6x + 12 = 0

<=> (x-2)(x-6) = 0

=> x = 2 or x = 6

Number of students in Ms. Sarno's  homeroom = 20

Number of female  in Ms. Sarno's  homeroom = 12

Number of Male  in Ms. Sarno's  homeroom = 20 - 12 = 8

Probability (Selecting Female act as “teacher’s helper.” )=

Probability (Selecting male act as “teacher’s helper.” )=

Out of Four options given , the best simulation describing above Situation is ,

Option (C) A bag of 15 marbles, with 9 marbles representing female students, has a marble drawn 4 times with replacement is best simulation describing above situation.

The reason being, if 9 marbles represent female students out of 15 marbles and we have to select 4 females for four months that is for January, February, March, and April.So, marbles are drawn 4 times with replacement .

Probability of choosing four female as teacher's helper for four months if a  bag of 15 marbles, with 9 marbles representing female students, has a marble drawn 4 times with replacement.  =