PLEASE HELP I WILL GIVE BRAINLIEST IF TWO PPL ANSWER!! :C Simplify (write without the absolute value sign):
|x - 120|, if x < -120
|x - ( -12 )|, if x > -12
|x - ( -12 )|, if x < -12
|x - ( - 12 )|, if x = -12
|x ÷3|, if x > 0
|x÷3|, if x < 0

x+120 , if x < -120

x+12 , if x > -12

x+12 , if x < -12

x+12 , if x = -12

x÷3 , if x > 0

x÷3 , if x < 0

Step-by-step explanation:

Well whatever is in the absolute value sign is always positive.

9514 1404 393

-x -120x +12-x -120x/3-x/3

Step-by-step explanation:

|x - 120|, if x < -120  . . .  the function changes behavior at x=120, at x < -120, the function value is -x+120

|x - ( -12 )|, if x > -12  . . .  in this domain, the function is unchanged: x + 12

|x - ( -12 )|, if x < -12  . . .  in this domain, the function is negated: -x -12

|x - ( - 12 )|, if x = -12  . . .  at this point, the function is 0

|x ÷3|, if x > 0  . . .  for positive x, the function is unchanged: x/3

|x÷3|, if x < 0  . . .  for negative x, the function is negated: -x/3

Both have the same jumping distance, I used mean to find the answer which is the average of the number.  First, you add all the numbers and then divided by how many numbers the operation had. In this case, 17+18+15= 50 divided by 3 equals to 16.67.