![224509](/avatars/18170.jpg)
224509
21.07.2021 •
Mathematics
Please help! look at picture!
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Ответ:
Step-by-step explanation:
2
= ![\frac{23}{8}](/tpl/images/1397/3530/f0144.png)
1
=
= ![\frac{14}{8}](/tpl/images/1397/3530/dcbda.png)
Ответ:
answer: a) car 1 : exponential function
car 2 : linear function
b) for car 1, function is,
for car 2, function is,
c) the price of car 2 is 1100.4 (approx) more than the price of car 1 after 9 years.
step-by-step explanation:
a) since the given table, for car 1,
x( number of years) 1 2 3
y ( value in dollars) 17390 16346.60 15365.8
while the table for car 2,
x( number of years) 1 2 3
y ( value in dollars) 17500 16500 15500
since, for car 1, in first year rate of change in car 1 is -1043.4
and in second year rate of change in car 1 is -980.8
which is not constant for every year.
therefore, if f(x) is a function shows the price of car 1 after x year.
then f(x) can not be linear ⇒ f(x) is exponential.
since, for car 2, the rate of change is
which is constant for every year.
therefore, if f'(x) is a function shows the price of car after x year.
then f'(x) must be linear.
b) let
thus, with of the first table,
a = 18500.00321 ≈ 18500 and b= 0.93999878 ≈ 0.94
thus, the function that shows the price of car 1 after x years,
let f'(x) = ax+b
for, x =1
f'(1) = a + b
but according to the above table f(1) = 17500
thus, a+b = 17500 )
similarly, 2 a + b = 16500 )
by solving equation (1) and (2)
we get, a = - 1000 and b= 18500
thus, the function that shows the price of car 2 after x years,
f(x) = - 1000x + 18500
c) after 9 year the price of car 1,
after 9 year the price of car 2,
thus, the difference between the price of car 1 and 2 after 9 years is,
10600.4038412-9500= 1100.40384123≈ 1100.4