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neilaamusic6966
03.12.2021 •
Mathematics
PLEASE HELP ME PLEASE!!
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Ответ:
Answer and Step-by-step explanation:
Alot of these can be solved with the table up above the problems.
A, B, and C.According to the table, every time a value has an exponent of 0, it would equal to 1. Since all A B and C values follow the 0 exponent, their value is 1.
D.According to the table, when we have a negative exponent, the number gets turned into a fraction of![\frac{1}{x^x}](/tpl/images/1156/7107/02329.png)
Since our value is 9^-2, do as followed :
Solve what is 9^2 :
![[\frac{1}{81} ]](/tpl/images/1156/7107/64c14.png)
E.This question is different, since we have to go backwards, we have to switch the negative exponent to a positive exponent and rid the fraction.
![x^5](/tpl/images/1156/7107/1332b.png)
F.Since we have one negative exponent, follow the fraction rule but instead of having one as the numerator, have 5a^3.
![\frac{5a^3}{b^{2}}](/tpl/images/1156/7107/d87cb.png)
Fill in the table :Since -3 is in parenthesis, we can rid the negative along with the parenthesis :
Follow the negative exponent rule :
Follow the negative exponent rule yet again :