thebasedgodchri
20.08.2020 •
Mathematics
Please Help multiple choice! Brainlest toooo babyyy
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Ответ:
C and D
Step-by-step explanation:
We want to find the equations where b=11 is a solution. Let's test each answer. choice. Plug 11 in for b and solve.
A. 2b= 211
2(11)=211
Multiply 2 and 11.
22≠211
22 does not equal 211, therefore this choice is not correct.
B. b+18=7
11+18=7
Add 11 and 18.
29 ≠ 7
29 does not equal 7, so this is not correct.
C. 77=7b
77=7(11)
Multiply 7 and 11.
77=77
77 does equal 77, so this is correct.
D. 9=b-2
9=11-2
Subtract 2 from 11.
9=9
9 equals 9, so this correct too.
E. 11=33/b
11=33/11
Divide 33 by 11.
11≠3
11 does not equal 3, so this is not the right choice.
b= 11 is a solution for C. 77-7b and D. 9=b-2
Ответ:
$.56 per can; $.49 per can; 5 cans for $2.45
Step-by-step explanation:
If it were a dollar for two cans, it's pretty easy to figure out each can is 50 cents. So you use the same idea. if you have x cans for y dollars, if you divide both numbers by x you get the price of 1 can.
3 cans for 1.68 is 1 can for 1.68/3 = .56 so 56 cents
5 cans for 2.45 is 1 can for 2.45/5 = .49 so 49 cents.
You could use this trick dividing by the price and find how many cans you need to but to pay 1 dollar.
3 cans for 1.68 is 3/1.68 for 1 dollar or 1.786 cans for 1 dollar. Doesn't make a lot of sense since you can't but part of a can, but I wanted to show you how you could use the logic for other things.