Please Help!
The area of a rectangle is x^2 + 7x + 6. What is the perimeter of this rectangle?

 The perimeter would be  2(x+1) + 2(x+6) or  4x + 14

Such a rectangle does not really exist!

If you factor and solve for x, you get {-1,-6} Real Rectangles cannot have negative dimensions.

Step-by-step explanation: Factoring to find out which theoretical dimensions were multiplied to get the imaginary area you get (x + 1) and (x + 6).

Perimeter is  Twice the length plus Twice the width. So substitute the "dimensions" into the formula to get 2(x+1) + 2(x+6)  distribute and simplify

2x + 2 + 2x + 12 = 4x + 14

20.33%

Step-by-step explanation:

We have that the mean (m) is equal to 87.5, the standard deviation (sd) 6.25 and the sample size (n) = 12

They ask us for P (x <86)

For this, the first thing is to calculate z, which is given by the following equation:

z = (x - m) / (sd / (n ^ 1/2))

We have all these values, replacing we have:

z = (86 - 87.5) / (6.25 / (12 ^ 1/2))

z = -0.83

With the normal distribution table (attached), we have that at that value, the probability is:

P (z <-0.83) = 0.2033

The probability is 20.33%