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tatiana4ever
25.02.2020 •
Mathematics
PLEASE HELP VERY IMPORTANT HELP
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Ответ:
Option B, x =![\frac{1 + ln(3)}{4}](/tpl/images/0522/3306/f0db7.png)
Step-by-step explanation:
e^4x-1 = 3
ln both side
ln(e^4x - 1) = ln(3)
ln(e) = 1
4x - 1 + 1 = ln(3) + 1
4x / 4 = (ln(3) + 1) / 4
x =![\frac{ln(3) + 1}{4}](/tpl/images/0522/3306/a3c33.png)
Option B, x =![\frac{1 + ln(3)}{4}](/tpl/images/0522/3306/f0db7.png)
Ответ: