mimi5261
23.07.2021 •
Mathematics
PLEASE HELP WILL MARK BRAINLIEST
Which is the solution to the inequality?
2 and three-fifths less-than b minus StartFraction 8 over 15 EndFraction
A. b less-than 2 and StartFraction 1 over 15 EndFraction
B. b greater-than 2 and StartFraction 1 over 15 EndFraction
C. b less-than 3 and StartFraction 2 over 15 EndFraction
D. b greater-than 3 and StartFraction 2 over 15 EndFraction
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Ответ:
Choice D
b greater-than 3 and StartFraction 2 over 15 EndFraction
In other words,
b > 3 & 2/15
or
========================================================
Explanation:
Let's convert the mixed number 2 & 3/5 into an improper fraction.
We'll use the rule
a & b/c = (a*c + b)/c
In this case, a = 2, b = 3, c = 5
So,
a & b/c = (a*c + b)/c
2 & 3/5 = (2*5 + 3)/5
2 & 3/5 = (10 + 3)/5
2 & 3/5 = 13/5
The inequality is the same as
---------------------
Let's multiply both sides by 15 to clear out the fractions
---------------------
Now isolate the variable b
Side note: Another way to go from 47/15 to 3 & 2/15 is to notice how
47/15 = 3 remainder 2
The 3 is the whole part while 2 helps form the fractional part. The denominator stays at 15 the whole time.
Ответ:
C. 26/100 because of 0.26 is just 26/100