PLease i need help with this

y = 2, if you plug into expressions for angles K and J they equal 80°

Step-by-step explanation:

from notations given it appears that ΔFKH is similar to ΔIJG, which means their angles are congruent

therefore, we can say that 4y² = 6y² - 40

-2y² = -40

y² = 20

y = √20 or 2√5

to find the measure in degrees, plug 2√5 into each expression:

4 · (2√5)² = 4 · 4 ·5 = 80°

6 · (2√5)² = (6 · 4 ·5) - 40 = 80°

answer:

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