Mathematics: Please I need this before 12pm

Please I need this before 12pm - id125209373, ninjapig647

Ответ:

letdou2670

19.01.2022

Mathematics

The required formula is:

$\ a_{n}=a_{1}+(n-1)d$

Step-by-step explanation:

The total number of squares of the the first term = 4

The total number of squares of the the second term = 7

The total number of squares of the the third term = 10

so,

a_1=4

a_2=7

a_3=10

Finding the common difference d

d=a_3-a_2=10-7=3

d=a_2-a_1=7-4=3

As the common difference 'd' is same, it means the sequence is in arithmetic.

If the initial term of an arithmetic progression is $a_{1}$ and the common difference of successive members is d, then the nth term of the sequence (a_n) is given by:

$\ a_{n}=a_{1}+(n-1)d$

Therefore, the required formula is:

$\ a_{n}=a_{1}+(n-1)d$

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Please I need this before 12pm

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