robert7248
20.09.2020 •
Mathematics
Please solve as fast as possible...
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Ответ:
In ∆ABD and ∆ACD
<BAD =<CAD ( each are half of <A )
<D=<D ( each equal to 90°)
AD = AD ( common)
So ∆ ABD is congruent to ∆ ACD.
Then AB =AC (by C.P.C.T)
Hence,∆ABC is an iso - sceles triangle.
Ответ:
im confused
Step-by-step explanation: