Mathematics: PLEASEEE HELP. Solve x^3-7x^2+6x-42=0

PLEASEEE HELP. Solve x^3-7x^2+6x-42=0 - id37264207541861, AlexGaming1822

Ответ:

whocares1819

02.02.2022

Factor by grouping

x^2(x-7) + 6(x-7) = 0 [took x^2 out of the first two and a 6 out of the last two]
(x-7)(x^2+6) = 0 [moved (x-7) out to the front]
x = -i sqrt(6) , i sqrt(6) , 7

only one real solution of x = 7

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Ответ:

mairealexander87

02.02.2022

Mathematics

$x^{3} -7 x^{2} +6x-42=0$

(x-7)

is a factor since it is a factor of -42 and 7 is a solution for f(x) to equal 0.

$(x-7)(a x^{2} +bx+c)=0$

$(x-7)( x^{2} +bx+6)=0$

$-7 x^{2} +b x^{2} =-7 x^{2}$

-7+b=-7