PLEASEEE HELPPPP U DONT HAVE TO BE CORRECT JUST HAS TO MAKE SENSEEE PLS HELLPP

TBH I don't really know either, but 63, 360?

Step-by-step explanation:

If they give you a number in feet, and they want inches time the number by 12? (12 inches in a foot)...sorry idrk...

Answer and Step-by-step explanation:

We are told that there are 5,280 feet in 1 mile.

We also know that 1 foot equals 12 inches.

So, to know how many inches are in One mile, we must multiply 5280 by 12.

     1    

  5280

×      12

 10560

+52800

63360

So, the amount of inches that are in 1 mile is 63,360.

#teamtrees #PAW (Plant And Water)

1. M is the midpoint of LN and O is the midpoint of NP. This makes the triangle MNO equal to half of LNP. Then you can get this equation
MO= (1/2) LP

If you insert MO = 2x +6 and LP = 8x – 20 the calculation would be:
2x+6= (1/2)( 8x-20)
2x+6= 4x-10
2x-4x= -10 - 6
-2x= -16
x=8

2. Centroid is the point that intersects with three median lines of the triangle. The centroid should divide the median lines into 1:2 ratio. In AC lines, A located in the base so A.F:FC would be 1:2

Then, the answer would be:
A.F= 1/(1+2) * AC
A.F= 1/3 * 12= 4

FC= 2/(1+2) * AC
FC= 2/3 * 12= 8

3. Since
∠BAD=∠DAC
∠ABD=∠ACD
AD=AD
The triangle ABD and ACD are similar. You can get this equation
BD=DC
x+8= 3x+12
x-3x= 12-8
-2x=4
x=-2

DC=3x+12= 3(-2) +12= 6

4. Orthocenter made by intersection of triangle altitude
A
BC lines slope would be (-4)-(-1)/1-4= -3/-3= 1. The altitude line slope would be -1, the function would be:
y=-x +a
0= 1+a
a=-1
y=-x-1
B
AC lines slope would be (-4)-(-1)/1-0= -3. The altitude line slope would be 1/3, the function would be:
y=1/3x+a
-1=1/3(4)+a
a=-7/3
y=1/3x - 7/3

C
BC lines slope would be (-1)-(-1)/4 = 0/4. 
The line would be 
0=x+a
a=-1
0=x-1
x=1

y=-x-1 = 1/3x-7/3
-x-(1/3x)=-7/3 +1
-4/3x= -4/3
x=1

y=-x-1
y=-1-1= -2
The orthocenter would be (1,-2)

5. 
a.Circumcenter: the intersection of perpendicular bisector lines
b.Incenter: the intersection of bisector lines
c.Centroid: the intersection of median lines
d.Orthocenter: the intersection of altitude lines