Plot the reflection of ABC across the x-axis. Give the coordinates of its vertices below. A(-2,3), B(6,3), and C(6, 8)

D. x = 10, m<TRS = 60°

Step-by-step explanation:

m<QRS = 122° (given)

m<QRT = (7x - 8)° (given)

m<TRS = (6x)° (given)

m<QRT + m<TRS = m<QRS (angle addition postulate)

(7x - 8)° + (6x)° = 122° (substitution)

Solve for x

7x - 8 + 6x = 122

Add like terms

13x - 8 = 122

13x = 122 + 8

13x = 130

x = 130/13

x = 10

✔️m<TRS = (6x)°

Plug in the value of x

m<TRS = (6*10)° = 60°