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keaganaplin

05.04.2022

Mathematics

$(x-2)^{2} +(y-5)^{2} =\sqrt{68}$

Step-by-step explanation:

Givens

The center of the circle is at (2,5).A point on the circumference is at (10,3).

First, we need to find the radius, which is the distance between the given points.

$d=\sqrt{(3-5)^{2} +(10-2)^{2} } =\sqrt{4+64}=\sqrt{68}$

Therefore, the radius of the circle is

$r \approx 8.25$

The explicit form of the equation of the circle would be

$(x-2)^{2} +(y-5)^{2} =\sqrt{68}$

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