Mathematics: PLS HELP 200 Σ j=1 2j( j + 3) Describe the steps to evaluate the summation. What is the sum?

PLS HELP 200 Σ j=1 2j( j + 3) Describe the steps

nayiiii1874

11.02.2022

Description:

Distribute 2j to (j+3).

Rewrite the summation as the sum of two individual summations.

Evaluate each summation using properties or formulas from the lesson.

The lower index is 1, so any properties can be used.

The sum is 5,494,000.

Step-by-step explanation:

Edge 2020

0,0(0 оценок)

lordcaos066

11.02.2022

Distribute 2j to (j+3).

Rewrite the summation as the sum of two individual summations.

Evaluate each summation using properties or formulas from the lesson.

The lower index is 1, so any properties can be used.

The sum is 5,494,000.

Step-by-step explanation:

EDGE 2021

0,0(0 оценок)

RioQNA

02.03.2023

See explanation below.

Step-by-step explanation:

Part A:

(i). They both correct because they could have a third degree polynomial that crosses the x-axis 3 times.

(ii). To find the zero's of the first one, set function equal to zero and use zero factor principle given as:

$\mathrm{Zero\:Factor\:Principle:\quad \:If}\:ab=0\:\mathrm{then}\:a=0\:\mathrm{or}\:b=0\:\left(\mathrm{or\:both}\:a=0\:\mathrm{and}\:b=0\right)$

So, we have:

$\mathrm{Solve\:}\:x+2=0:\quad x=-2\\\\\mathrm{Solve\:}\:x-1=0:\quad x=1\\\\\mathrm{Solve\:}\:x-2=0:\quad x=2$

0,0(0 оценок)