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27.04.2021 •
Mathematics
Pls help, simple, and not that hard
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Ответ:
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Explanation:
Let's solve (x-2)(x-5) = 0 and doing so leads to x = 2 or x = 5. Plugging either value in for x makes the expression (x-2)(x-5) become 0.
Let's pick a value to the left of x = 2, let's say we pick x = 0. Plug this into the expression (x-2)(x-5) and we get the following:
(x-2)(x-5)
(0-2)(0-5)
(-2)(-5)
10
The result is a positive number, meaning that (x-2)(x-5) is positive when we select a value smaller than 2.
Now we'll repeat this with a value between 2 and 5. Let's say we pick on x = 3.
So,
(x-2)(x-5)
(3-2)(3-5)
(1)(-2)
-2
The result is negative, so (x-2)(x-5) is negative when 2 < x < 5. This immediately rules out choices C and E.
Unfortunately, answer choices B and D won't work either for similar reasoning. The only thing left is choice A.
Side note: The answer in interval notation is
so basically it's everything but values between 2 and 5; however, x = 2 and x = 5 are part of the solution set.
Another side note: if you flip the inequality sign from
to
, then the answer would be choice C.
Ответ:
Triangular Pyramid
Step-by-step explanation: