mikurrjurdan
13.05.2021 •
Mathematics
Plsss helppp
Talia had solved the equation x2 – 2x – 5 = ( using the Quadratic Formula. She got x = 3
and a
-1 as her answers. Her teacher let her know that she got the question incorrect.
Work through the problem and determine what she may have done incorrectly and describe
that in the space below.
Solved
Show answers
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Ответ:
see below
Step-by-step explanation:
A. f(x) = 4x^2 - 7x - 15
We need the numbers to multiply to- 15
1*15 and 3*5
One of the terms multiplies by 4 (or 2)
Try 4 first
4*-3 +5 = -7 That works
-3+5 = -15
f(x) = (4x+5)(x-3)
B. We want the x intercepts so set equal to 0
0 = (4x+5)(x-3)
Using the zero product property
0 = 4x+5 x-3 =0
-5 = 4x x=3
-5/4 =x x=3
C End behavior
Let x be negative infinity
The function is dominate by 4x^2
f(-∞) = 4 ( -∞) ^2 = 4 (∞) = ∞
At negative infinity the functions goes to infinity
Let x be infinity
The function is dominate by 4x^2
f(∞) = 4 ( ∞) ^2 = 4 (∞) = ∞
At infinity the functions goes to infinity
Part D:
We know the zeros at 3 and -5/4
We know the vertex is at halfway between the zeros
(3 -5/4) /2 = 7/4 /2 = 7/8
Since the parabola opens up (The coefficient of the x^2 term is positive), we know we have a minimum.
f(7/8) = 4 (7/8)^2 -7(7/8) -15 = 4(49/64) -1/8 -15 =-289/16
We know the minimum the zeros and the end behavior, we can graph the functions