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KArrington815
17.09.2019 •
Mathematics
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i'll give 30 points, brainliest and 5 stars to the first correct answer
a rock is thrown upward with a velocity of 21 meters per second from the top of a 44 meter high cliff, and it misses the cliff on the way back down. when will the rock be 5 meters from the water, below? round your answer to two decimal places.
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Ответ:
The answer to your question is: t = 3.54 s
Step-by-step explanation:
data
vo = 21 m/s
height of the cliff = 44 m
t= ? when the rock be 5 meters from the water.
Process
First, calculate the distance the rock reach in its way up.
h max = vo² /2g = (21)² / 2(9.81) = 22.5 m
total height = 44 m + 22.5 m = 66.5 m
but we need to calculate the time when the rock be 5 m from the water so,
height = 66.5 - 5 m
height = 61.5 m
Now, use free fall formulas to calculate time
h = gt² / 2
61.5 = (9.81)t² / 2
solve for t
2(61.5) = 9.81t²
123 = 9,81t²
t² = 123 / 9.81
t² = 12.53
t = 3.54 s
Ответ:
2) 108
3) 518
4) 68
5) 238
6) 348
7) 18
8) 28
9) 368
10) 978