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orladuffy1
28.06.2019 •
Mathematics
Plzzz ! marie mixes 16 liters of 18% acid solution with a 27% acid solution, which results in 21% acid solution. let x represent the number of liters of 27% solution used and let y represent the number of liters of mixture. which system of equations can be used to find the number of liters of 27% acid solution in the mixture? 1. y = x + 16; 0.27y = 0.21x + 2.88 2. y = x + 16; 0.21y = 0.27x + 2.88 3.y = x + 16; 0.21y = 0.27x + 4.32 4. y = x + 16; 0.27y + 2.88x = 0.21
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Ответ:
2. y = x + 16; 0.21y = 0.27x + 2.88
Step-by-step explanation:
You have two conditions:
Volume of 18 % + volume of 27 % = volume of 21 % Mass of acid in 18 % + mass of acid in 27% = mass of acid in 21 %For the first condition,
16 + x = y Transpose
(1) y = x + 16
For the second condition
V₁c₁ + V₂c₂ = V₃c₃
16×0.18 + 0.27x = 0.21y
2.88 + 0.27x = 0.21y Transpose
(2) 0.21y = 0.27x + 2.88
The system of equations is y = x + 16; 0.21y = 0.27x + 2.88
Ответ:
6 hours & 30 minutes
Step-by-step explanation: