Point B has coordinates (3,2). The x-coordinate of point A is negative 9. The distance between point A and point B is 15 units. What are the possible coordinates of point A?

(-9,9) or (-9,-7) are the possible coordinates

Step-by-step explanation:

We can use the formula for the distance between two points to get this

Mathematically, this can be;

d = √(x2-x1)^2 + (y2-y1)^2

Now let our point A be (x1,y1) = (-9,n)

let’s say y1 is n for now

For point B, we have (x2,y2) = (3,2)

and our d is 15 units

Inputing the values, we have

15^2 = (3+9)^2 + (2-n)^2

225 = 144 + (2-n)^2

225-144 = (2-n)^2

(2-n)^2 = 81

(2-n) = √(81)

2-n = -9

or 2-n = 9

n = 11 or n = -7

Now the possible coordinate values of point A are;

(-9,9) or (-9,-7)

  80 ÷ 16 = 5

Step-by-step explanation:

The "family facts" seem to be related to the relationship ...

  5 × 16 = 80

One of the facts is generated from this one by reversing the order of the factors:

  16 × 5 = 80

The other two are found by dividing the equation by one or the other of the factors:

  16 = 80/5 . . . . . divide by 5

  5 = 80/16 . . . . . divide by 16

This last one is the one that is missing. It the form used in the problem statement, it is ...

  80 : 16 = 5