Mathematics: Point charges q1 = 2.0 µc and q2 = 4.0 µc are located at →r 1 = (4.0 i ^ − 2.0 j ^ + 5.0k ^ )m and →r 2 = (8.0 i ^ + 5.0 j ^ − 9.0k ^ )m . what is the force of q2 on q1 ?

Point charges q1 = 2.0 µc and q2 = 4.0 µc are located

Ответ:

chloebaby8

04.01.2022

Mathematics

Given two point charges q_1

and

which are a distance $r_{12}$ apart.

The force $\overrightarrow{F}$ on one of the charges is proportional to the magnitude of its own charge and inversely proportional to the square of the distance between them.
i.e.
$\overrightarrow{F}= \frac{k_e|q_1q_2|}{r_{12}^2}$

where k_e

is the constant of proportionality $8.99\times10^9 \ Nm^2C^{-2}$

Given that $q_1=2.0\mu C$ and $q_2=4.0\mu C$

Also, given that r_ 1 = (4.0i-2.0 j+5.0k)

m and

m, then

$|r_{12}|=|r_2-r_1| \\ \\ =|(8.0 i+ 5.0 j-9.0)-(4.0i-2.0 j+5.0k)| \\ \\ =|4.0i+7.0j-14k|= \sqrt{4^2+7^2+(-14)^2} = \sqrt{16+49+196} \\ \\ = \sqrt{261} =16.2 \ m$

Therefore, the force of q_2

is given by

$\overrightarrow{F}= \frac{8.99\times10^9\cdot2\times10^{-6}\cdot4\times10^{-6}}{(16.2)^2} \\ \\ = \frac{7.192\times10^{-5}}{261} =2.76\times10^{-7} \ N$

0,0(0 оценок)

Ответ:

xojade

25.02.2020

Mathematics

4 blocks west, 6 blocks south

Step-by-step explanation: east and west are opposites 5-1=4 blocks west. 4+2=6 blocks south. the direction would be south-west.

0,0(0 оценок)

Point charges q1 = 2.0 µc and q2 = 4.0 µc are located at →r 1 = (4.0 i ^ − 2.0 j ^ + 5.0k ^ )m and →r 2 = (8.0 i ^ + 5.0 j ^ − 9.0k ^ )m . what is the force of q2 on q1 ?

Ответ:

Ответ:

Ask your question to the AI advisor

More tips

Answers on questions: Mathematics

Ask an AI advisor a question