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sil91
19.07.2019 •
Mathematics
Points a(-2,3), b(-5,-4), and c(2,-1) form triangle abc on a coordinate plane. what is the area of this triangle in square units? 40 29 20
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Ответ:
d = root ((x2-x1) ^ 2 + (y2-y1) ^ 2)
We have then:
For AB:
AB = root ((- 5 - (- 2)) ^ 2 + (-4-3) ^ 2)
AB = 7.615773106
For AC:
AC = root ((2 - (- 2)) ^ 2 + (-1-3) ^ 2)
AC = 5.656854249
For BC:
BC = root ((2 - (- 5)) ^ 2 + (-1 - (- 4)) ^ 2)
BC = 7.615773106
The area is:
A = root ((s) * (s-a) * (s-b) * (s-c))
Where,
s = (a + b + c) / 2
Substituting values:
s = (7.615773106 + 5.656854249 + 7.615773106) / 2
s = 10.44420023
A = root ((10.44420023) * (10.44420023-7.615773106) * (10.44420023-5.656854249) * (10.44420023-7.615773106))
A = 20 units ^ 2
The area of this triangle in square units is:
A = 20 units ^ 2
Ответ:
boston
Explanation:
because