Mathematics: Prove that: a) 5^31–5^29 is divisible by 100. the answer should be in this format: * 100 b) 25^9+5^17 is divisible by 30. the answer should be in this format: * 30 c) 27^10–9^14 is divisible by 24. the answer should be in this format: * 24

Prove that: a) 5^31–5^29 is divisible by 100. - id5315291001609797, taijaababy

Ответ:

lanman65

15.03.2022

(a) 5^31-5^29 = 5^29(5^2-1)

= 5^29(24)
= 5^29(6)(4)
=5^26(6)*[(5)(5)(4)]
=5^26(6)*100
(b) 25^9+5^17 = 5^18+5^17
=5^17(5+1)
=5^17(6)
=5^16[(5)(6)]
=5^16*30
(c) 27^10â€“9^14 = 3^30-3^28
=3^28(3^2 -1)
=3^28(8)
=3^27[(3)(8)]
=3^27*24

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Ответ:

star296

21.09.2020

Mathematics

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Prove that: a) 5^31–5^29 is divisible by 100. the answer should be in this format: * 100 b) 25^9+5^17 is divisible by 30. the answer should be in this format: * 30 c) 27^10–9^14 is divisible by 24. the answer should be in this format: * 24

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