Prove that the sum of 2 even integers is an even integer

Let a and b represent even integers. Then by definition of an even integer, we can say that:  a = 2n and b = 2m

Proof by contradiction:

a + b is not an even integer.

Using substitution, 2n + 2m is not an even integer.

Using distibutive property, 2(n + m) is not an even integer.

Consider that (n + m) = k, then we have 2k is not an even integer.

This is a False statement since 2 times any integer is an even integer.

Therefore, a + b is an even integer, so the sum of two even integers is an even integer.  QED

any value for t can make this true.

Step-by-step explanation:

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