Prove the identity
(cot x sin x)(sec x – cos x) = sin^2x

Step-by-step explanation:

[(cosx/sinx)(sinx)][(1/cosx) - cosx]

(cosx)[(1 - cos²x)/cosx]

1 - cos²x

sin²x

The complete question is
Which table represents the same relation as the set {(-6,4),(-4,0),(-3,2),(-1,2)}?

we know that
in the set

for the point (-6,4)
x=-6
y=4

for the point (-4,0)
x=-4
y=0

for the point (-1,2)
x=-1
y=2

for the point (-3,2)
x=-3
y=2

the table will be
x    y  
-6   4
-4   0
-3   2
-1   2

therefore

the answer is
the option B

the solution in the attached figure