Prove: The square of a number that is one more than a multiple of 3 is also one more than a multiple of 3.
(3n + 1)^2= 9n^2 +6n+1
= ? (?n^2 + ?n) + ?
= 1 more than multiple of 3

The missing term is 2x^2.

Step-by-step explanation:

The given expression is (10x - 4x^2) - (7x +___) = 3x - 6x^2

Let's take the missing term "a"

10x - 4x^2 - 7x - a = 3x - 6x^2

Simplify the like terms

3x - 4x^2 - a = 3x - 6x^2

3x -3x - 4x^2 +6x^2 = a

0 + 2x^2 = a

a = 2x^2

Therefore, the missing term is 2x^2.

Thank you.