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30.06.2019 •
Mathematics
Qsrt is a parallelogram with diagonals qs— and rt— intersecting at point a. if rt—=x+15 and ra—=2x+3, what is the length of rt—?
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Ответ:
Length of RT is, 18 units.
Step-by-step explanation:
Given : QSRT is a parallelogram with diagonals are QS and RT intersecting at point A.
In parallelogram properties:
Diagonals of a parallelogram bisect each other.Also, Diagonal of a parallelogram separates it into two congruent.Diagonal (RT) = RA +TA
From the parallelogram properties; RA = TA
then:
RT = RA +RA
RT = 2RA
Substitute the given values of RT = x+15 unit and RA =2x+3 unit in above expression we have;
x + 15 = 2(2x+3)
Using distributive property i.e,
x + 15 = 4x + 6
Subtract x from both sides we get;
x +15-x = 4x + 6 -x
Simplify:
15 = 3x + 6
Subtract 6 from both sides we get;
15 - 6 = 3x+6 -6
Simplify:
9 = 3x
Divide both sides by 3 we get;
Simplify:
x = 3
Substitute the value of x in RT we have;
RT = x+15 = 3+15 =18
Therefore, the length of RT is, 18 units
Ответ:
0=12
Step-by-step explanation
(5−2)(2−2)=12
(3)(2−2)=12