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rafeychoudhry4571
05.05.2020 •
Mathematics
Quadrilateral PQRSis graphed in the coordinate plane.
To the nearest tenth, what is the perimeter of quadrilateral PQRS?
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Ответ:
33.6
Step-by-step explanation:
As we can see in the graph, the points:
P is located at (-2, 8)Q is located at ( 6, 8) R( is located at (6, 2) S is located at (-5, 0)To find a distance between two points or the length of the segment, we use the following formula:
Because the two points P and Q are located at the same libe y = 8
=> the lenght of PQ =![\sqrt{(6- (-2))^{2} } = \sqrt{8^{2} } = 8\\](/tpl/images/0638/1146/5cacb.png)
Because the two points R and Q are located at the same libe x = 6
=> the length of RQ =![\sqrt{(8-2)^{2} } = \sqrt{6^{2} } = 6\\](/tpl/images/0638/1146/db4e5.png)
The lenght of RS is:
= ![\sqrt{125} = 11.1](/tpl/images/0638/1146/ff4a4.png)
The lenght of SP is:
= 8.5
=> the perimeter of quadrilateral PQRS = PQ+RQ+RS+SP
= 8+6+11.1+8.5
= 33.6
Ответ:
length of segment YZ is 8 cm
Step-by-step explanation:
given data
AB = 16 cm
DA = 3
cm
AB and DA form interior angle = 45-degre
WX ≠ YZ
WX = 16 cm
to find out
length of segment YZ
solution
area of △ABD is the same as the area of △BCD
and
area of △ABD is express as
area of △ABD = AB × AD × sin(45) ÷ 2 ............1
put here value
area of △ABD = 16 × 3√2 × sin(45) ÷ 2
area of △ABD = 24
and
area of the parallelogram is
area of the parallelogram = 24 × 2
area of the parallelogram = 48
so
now we will consider here YZ = x
and Since ZY XW is isosceles trapezoid
so here we can say that
WM = ZM = (16 - x) ÷ 2 .......................2
so area of trapezoid will be
area of trapezoid =
.......................3
area of trapezoid =
48 =
solve it we get
x = 8
so length of segment YZ is 8 cm