Qual o valor do produto (-4x²y).(-3xy) ?
A) -7xy
B) -12x³y
C) 12x³y²
D) -12x³y²

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Ответ:

jamaiciaw6

28.05.2023

Mathematics

The first option is correct.

Step-by-step explanation: Given that the vertices of square PQRS are P(−4, 7), Q(5, 4), R(2,−5) and S(−7,−2). So, PR and QS are its two diagonals.

First, we will measure PR and QS as follows.

$PR=\sqrt{(2+4)^2+(-5-7)^2}=\sqrt{36+144}=\sqrt{180}=3\sqrt{20},\\\\QS=\sqrt{(-7-5)^2+(-2-4)^2}=\sqrt{144+36}=\sqrt{180}=3\sqrt{20}.$

Therefore, PR = QS = 3√20.

Now, slope of PR is

$m_1=\dfrac{-5-7}{2+4}=-2$

and slope of QS is

$m_2=\dfrac{-2-4}{-7-5}=\dfrac{1}{2}.$

Hence, PR ⊥ QS.

Again, mid-point of PR is

$\left(\dfrac{-4+2}{2},\dfrac{7-5}{2}\right)=(-1,1),$

and mid-point of QS is

$\left(\dfrac{5-7}{2},\dfrac{4-2}{2}\right)=(-1,1).$

Thus, the correct option is

$(a)~~\textup{PR}=\textup{QS}=3\sqrt{20}.\\\\\textup{Slope of PR} =-2,~\textup{and slope of QS}=\dfrac{1}{2}.\\\\so~PR\perpQS,~(-1,1)~\textup{is the mid-point of PS and QS},\\\\so,~\textup{PR and QS bisect each other}.$

The vertices of square pqrs are p(−4, 7), q(5, 4), r(2,−5) and s(−7,−2). which of the following show

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Qual o valor do produto (-4x²y).(-3xy) ? A) -7xy B) -12x³y C) 12x³y² D) -12x³y²