Mathematics: Question 1(Multiple Choice Worth 2 points) (01.06) Determine the quotient of 2 over 3 divided by 4 over 5. 8 over 15 10 over 12 2 over 3 1 and 2 over 10

Question 1(Multiple Choice Worth 2 points) (01.06)

devinfolds

02.02.2022

10 over 12

Step-by-step explanation:

Given the expression, $\frac{2}{3} \div \frac{4}{5}$ we are to determine the quotient which is as shown;

Given

$\frac{2}{3} \div \frac{4}{5}$

multiply $\frac{2}{3}$ with the reciprocal of $\frac{4}{5}$ i.e $\frac{5}{4}$

$\frac{2}{3} \times \frac{5}{4}$

simplify the resulting expression

$= \frac{2}{3} \times \frac{5}{4}\\\\= \frac{10}{12} \\\\= \frac{2\times5}{2\times 6} \\\\$

$= \frac{5}{6}$

Hence the quotient is 10 over 12 OR 5 over 6

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kim643

02.08.2020

The coach should start recruiting players with weight 269.55 pounds or more.

Step-by-step explanation:

We are given the following information in the question:

Mean, μ = 225 pounds

Standard Deviation, σ = 43 pounds

We are given that the distribution of weights is a bell shaped distribution that is a normal distribution.

Formula:

$z_{score} = \displaystyle\frac{x-\mu}{\sigma}$

We have to find the value of x such that the probability is 0.15

$P( X x) = P( z \displaystyle\frac{x - 225}{43})=0.15$

$= 1 -P( z \leq \displaystyle\frac{x - 225}{43})=0.15$

$=P( z \leq \displaystyle\frac{x - 225}{43})=0.85$

Calculation the value from standard normal z table, we have,

P(z < 1.036) = 0.85

$\displaystyle\frac{x - 225}{43} = 1.036\\\\x = 269.548 \approx 269.55$

Thus, the coach should start recruiting players with weight 269.55 pounds or more.

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