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isabelsmhl
26.10.2021 •
Mathematics
Question 17 of 25
Given any triangle ABC with corresponding side lengths a, b, and c, the law of
cosines states:
B
a
A
b
A. 02 = a + b2 - 2 bc cos(B)
B. 2 - a² + 6 - 2abcos(C)
O c. c = a - - 2bccos(C)
OD. of - +62 - 2bc cos(A)
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Ответ:
0.083
Step-by-step explanation: