Question 3 of 10
2 Points
Which situation shows a constant rate of change?
O
A. The number of goals scored in a soccer game compared with the
minutes played
B. The weight of a kitten compared with its age in months
O
C. The amount raised by a booster club compared with the number
of raffle tickets sold
O
D. The height of a paper airplane over time

it's c A constant rate of change is accomplished when the change in one situation constantly results in changing another. In the scenario of a booster club constantly selling raffle tickets, the more tickets they sold the more the club raises.

Explanation:

Label the center point of the circle as point G.

Also, label the top and bottom tangent points as H and J respectively. This means that H is on line segment ED, while J is on line segment EF.

The given arc measure of 100 degrees directly leads to the central angle HGJ to be 100 degrees.

Focus on quadrilateral EHGJ. It has two right angles at points H and J since they are tangent points. Angle G of this quadrilateral was found to be 100. Let's find angle E

E+H+G+J = 360 any four angles of a quadrilateral add to 360

E+90+100+90 = 360

E+280 = 360

E = 360-280

E = 80

Or as a shortcut, we can note that angles E and G must add to 180, since H+J = 90+90 = 180, making up half of 360.

So, E+G = 180 leads to E+100 = 180 which solves to E = 80.

Once we know that E = 80, this leads to angle DEF to be 80 degrees.

This is an inscribed angle that subtends arc DF. By the inscribed angle theorem, we double the inscribed angle value to get the arc measure

arc DF = 2*(inscribed angle DEF)

arc DF = 2*(80)

arc DF = 160 degrees