Question 9 (1 point)
Solve for X
K
50°
110°
P
R
w
30x

x = 3

Step-by-step explanation:

Recall: Opposite angles in an inscribed quadrilateral are supplementary.

Thus,

m<R = 180 - m<P

m<R = 180 - 110

m<R = 70°

Recall: measure of inscribed angle = half of the intercepted arc

Thus:

m<R = ½(arc KPQ)

70 = ½(50 + 30x)

Multiply both sides by 2

2*70 = 50 + 30x

140 = 50 + 30x

140 - 50 = 50 + 30x - 50

90 = 30x

90/30 = 30x/30

3 = x

x = 3