Mathematics: Question 9 solve the following system of equations using matrices. y = 2x – 1 6x – y = 13 (3, 5) (-3, 5) (5, 0)

C. $4,460Step-by-step explanation:The monthly profit made, is a function of the price of each sign, x. Given the function that represents that models the monthly profit, , if the price, x, is $20, the monthly profit can be solved by simply plugging in the vakue if x into the given function equation as shown below:The monthly profit is $4,460....

Question 9 solve the following system of equations

Ответ:

Hellokittyjam35

11.03.2022

Mathematics

we are given two system of equations

First equation is

y=2x-1

we can write as

-2x+y=-1

Second equation is

6x-y=13

now, we can find augmented matrix

$A=\begin{pmatrix}-2&1&-1\\ 6&-1&13\end{pmatrix}$

now, we can change it into reduced row echelon form

step-1: multiply the 1st row by -1/2

$A=\begin{pmatrix}-1&-1/2&1/2\\ 6&-1&13\end{pmatrix}$

step-2: add -6 times the 1st row to the 2nd row

$A=\begin{pmatrix}-1&-1/2&1/2\\ 0&2&10\end{pmatrix}$

step-3:multiply the 2nd row by 1/2

$A=\begin{pmatrix}-1&-1/2&1/2\\ 0&1&5\end{pmatrix}$

step-4:add 1/2 times the 2nd row to the 1st row

$A=\begin{pmatrix}1&0&3\\ 0&1&5\end{pmatrix}$

so, we will get

x=3,y=5

Answer is (3,5)

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Ответ:

abilovessoftball

02.04.2022

Mathematics

C. $4,460

Step-by-step explanation:

The monthly profit made, is a function of the price of each sign, x. Given the function that represents that models the monthly profit, f(x) = -10x^2 + 498x - 1,500 , if the price, x, is $20, the monthly profit can be solved by simply plugging in the vakue if x into the given function equation as shown below:

f(20) = -10(20)^2 + 498(20) - 1,500

f(20) = -4,000 + 9,960 - 1,500

f(20) = 4,460

The monthly profit is $4,460.

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Question 9 solve the following system of equations using matrices. y = 2x – 1 6x – y = 13 (3, 5) (-3, 5) (5, 0)

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