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sarahhfaithhh
19.12.2020 •
Mathematics
Question
Find the equation of the line that is perpendicular to the given line and passes through the given point.
Enter your answer in slope-intercept form (y = mx + b ) with the values of m and b given as decimals,
rounded to the nearest hundredth if necessary.
y = 10x ; (6,-4)
The equation is y =
PLEASE ANSWER QUICKLY !!!
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Ответ:
Step-by-step explanation:
The point-slope form of equation of a line is:
y - y₀ = m(x - x₀)
where (x₀, y₀) is the point which the line passes through and m is the slope of the line
The product of slopes of two perpendicular lines is -1
so if given lines slope is 10 them:
10·m = -1
m = -0.1
(6, -4) ⇒ x₀ = 6, y₀ = -4
Therefore:
y - (-4) = -0.1(x - 6)
y = -0.1x + 0.6 + (-4)
y = -0.1x - 3.4
Ответ: