keltaylor
17.02.2021 •
Mathematics
Question : \int_{5}^{8} 2x^2 e^{4x} dx∫
5
8
2x
2
e
4x
dx
e^{20}(481e^{12} - 181)e
20
(481e
12
−181)
\frac{1}{16}e^{20}(481e^{12} - 181)
16
1
e
20
(481e
12
−181)
\frac{1}{4}e^{20}(481e^{12} - 181)
4
1
e
20
(481e
12
−181)
\frac{1}{8}e^{20}(481e^{12} - 181)
8
1
e
20
(481e
12
−181)
plz help, u win something if u solve this
Solved
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Ответ:
Step-by-step explanation:
y = -x²+8x-12
= -(x²-8x) - 12
= -(x²-8x+4²)+4²-12
= -(x-4)² + 4
vertex (4,-4)
axis of symmetry: x = 4