Mathematics: Radium-226, a common isotope of radium, has a half-life of 1,620 years. how many grams of a 120-gram sample will remain after t years? which equation can you use to solve this problem?

Radium-226, a common isotope of radium, has a half-life

Ответ:

Arden990560

06.01.2022

Mathematics

$y=120*(\frac{1}{2})^{\frac{t}{1620}}$

Step-by-step explanation:

We have been given that Radium-226, a common isotope of radium, has a half-life of 1,620 years.

We will use half life formula to solve our given problem.

$y=a*(\frac{1}{2})^{\frac{t}{h}}$ , where,

$a=\text{Initial value}$ ,

$t=\text{Time}$ ,

$h=\text{Half life}$ .

As we are told that the sample has 120 grams, this means that a equals 120. Upon substituting our given values in half life formula we will get,

$y=120*(\frac{1}{2})^{\frac{t}{1620}}$

Therefore, the equation $y=120*(\frac{1}{2})^{\frac{t}{1620}}$ represents the remaining amount of Radium-226 after t years.

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Ответ:

harveyangel123p2tjae

06.01.2022

Mathematics

The equation $y=120*(\frac{1}{2}) ^{\frac{t}{1620} }$ represents the remaining amount of Radium-226 after t years.

Given:

The half-life of a common isotope of radium (Radium-226) = 1,620 years

Initial value (a) = 120 gram

We will use the half-life formula to solve our given problem.

$y=a*(\frac{1}{2} )^{\frac{t}{h} }$

Where,

a = Initial value

h = Half life

t = Time

So,

$y=120\times(\frac{1}{2}) ^{\frac{t}{h} } \\y=120\times(\frac{1}{2}) ^{\frac{t}{1620} }$

Therefore, the equation $y=120*(\frac{1}{2}) ^{\frac{t}{1620} }$ represents the remaining amount of Radium-226 after t years.

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Ответ:

IsabellaGracie

15.07.2022

Mathematics

good

Step-by-step explanation:

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Radium-226, a common isotope of radium, has a half-life of 1,620 years. how many grams of a 120-gram sample will remain after t years? which equation can you use to solve this problem?

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