Randolph is trying to find the equation of a line parallel to y = x − 6 in slope-intercept form that passes through the point (−1, 5). which of the following equations will he use?
y − 5 = 1/4 (x − (−1))
y − (−1) = 1/4 (x − 5)
y − 5 = −4(x − (−1))
y − (−1) = −4(x − 5)

Here, Equation of a Line = y = x - 6
Line which is parallel, must have similar slope i.e, 1

Now, Coordinates are (-1, 5)
We know, principle equation, y - y1 = m(x - x1)
y - 5 = 1 (x + 1)

[ Please check your options, it is none of them ]

y - 5 = x + 1
y = x + 6

Hope this helps!

The value of x is 38°

Step-by-step explanation:

Given: ∠SRT ≅ ∠STR, m∠SRT = 28°, m∠STU = 4x

We are given ∠SRT = ∠STR

But ∠SRT = 28°

Therefore, ∠STR = 28°

Supplementary Angle: Sum of of two angles on straight line is 180°

∠STR + ∠STU = 180°

   28° +  4x     = 180°

                4x  = 180 - 28

                4x  = 152

                  x  = 38°

Hence, The value of x is 38°