Rectangle a has a length of 24 meters and a width of 20 meters. rectangle b has the same area as rectangle a. the width of rectangle b is 12 meters less than the width of rectangle a. what is the length of rectangle b ?

To solve this, first we'll find the area of the rectangle A,

Area=length × width
?=24m×20m
480m=24m×20m
480m squared=area of the rectangle A

now we'll find the width of rectangle B,
"the width of rectangle B is 12 meters less than the width of rectangle A",
20m-12m= 8m
8m=width of rectangle B

finally we'll find the length of rectangle B,
area of the rectangle B= 480msquared
width= 8m
length=? (to find this divide the area by the width)
480÷8=60m
length of the rectangle B=60m

8x² - 5y² + 5xy

Step-by-step explanation:

8x² + 7xy - 6y² + 4x² - 3xy + 2y² - 4x² + xy - y² = (8x² + 4x² -4x²) + (-6y² + 2y² - y²) + (7xy - 3xy + xy) = 8x² - 5y² + 5xy