Mathematics: Researchers measured the data speeds for a particular smartphone carrier at 50 airports. the highest speed measured was 78.2 mbps. the complete list of 50 data speeds has a mean of x overbarequals18.22 mbps and a standard deviation of sequals23.87 mbps. a. what is the difference between carrier s highest data speed and the mean of all 50 data speeds? b. how many standard deviations is that [the difference found in part (a)]? c. convert the carrier s highest data speed to a z score. d. if we consider

The correct answer I believe is d...

Researchers measured the data speeds for a particular

neekog11

06.01.2022

The highest speed measured was 78.2 Mbps.

n = 50

$\bar {x}=18.22$

s= 23.87

a)What is the difference between carrier's highest data speed and the mean of all 50 data speeds?

= 78.2 - 18.22

=59.98

b)How many standard deviations is that [the difference found in part (a)]

= $\frac{difference }{s} = \frac{59.98}{23.87}=2.5127$

c) Convert the carrier's highest data speed to a z score.

$z=\frac{78.2 - 18.22}{23.87}$

z=2.512

d) If we consider data speeds that convert to z scores between minus2 and 2 to be neither significantly low nor significantly high

Yes the carrier's highest data speed is significant because it is greater than 2.

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