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kcombest2979
21.10.2019 •
Mathematics
Rewrite each expression so that each term is in the form kxn, where k is a real number, x is a positive real number,
and n is a rational number.
x^(−2/3) ∙ x^(1/3)
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Ответ:
So the equation in standard form will be
Step-by-step explanation:
We have given equation![x^{\frac{-2}{3}}\times x^{\frac{1}{3}}](/tpl/images/0338/6471/f134e.png)
We have to write this expression in standard form
For writing in standard form first we have to do operation on the expression
We know that there is property of exponent that when two functions are multiplied with each other then there exponent are added
So![x^{\frac{-2}{3}}\times x^{\frac{1}{3}}=x^{\frac{-2}{3}+\frac{1}{3}}=x^{\frac{-1}{3}}](/tpl/images/0338/6471/d4ef0.png)
So the equation in standard form will be![x^{\frac{-1}{3}}](/tpl/images/0338/6471/42b0e.png)
Ответ:
x^3 - 14 - 2x^2 - 9x You move the -14 To get. X^3-2x^2-9x-14