Rewrite without absolute value for the given conditions: y=|x-3|+|x+2|-|x-5|, if 3 If you put a link i will not hesitate to report you

Don't know if this is right but it should maybe be y= x+3+x+2-x+5 because You cant have a negative in absolute values.

4x^2 + 8x - 12 = 0

Step-by-step explanation:

A quadratic equation with roots a and b has the equation (x - a)(x - b) = 0.

You roots are 1 and -3.

The equation is

(x - 1)(x - (3)) = 0

(x - 1)(x + 3) = 0

We can multiply it out.

x^2 + 3x - x - 3 = 0

x^2 + 2x - 3 = 0

Since we need the leading coefficient to be 4, we multiply both sides by 4.

4x^2 + 8x - 12 = 0