Mathematics: Right triangle abc is located at a (−1, −2), b (−1, 1), and c (3, 1) on a coordinate plane. what is the equation of a circle a with radius segment ac? (x + 1)2 + (y + 2)2 = 9 (x + 1)2 + (y + 2)2 = 25 (x − 3)2 + (y − 1)2 = 16 (x − 3)2 + (y − 1)2 = 25

The expression that is equivalent to 27+45 would be a. 8(19+37)...

Right triangle abc is located at a (−1, −2), b (−1,

Ответ:

carlos113101

24.09.2019

Mathematics

answer:

step-by-step explanation:

use the distance formula to find the length of ac

$d=\sqrt{(x_{2}-x_{1})^2+(y_{2}-y_{1})^2} }$ $d = \sqrt{())^2+())^2}d = \sqrt{(3+1)^2 + (1+2)^2} d=\sqrt{(4)^2+(3)^2} d=\sqrt{16+9}\\ \\d=\sqrt{25}\\ \\d= 5$

the circle equation is in the format $(x-h)^2+(y-k)^2=r^2$ , with the center being at the point (h, k) and the radius being r

ac = 5, so r = 5

the center of circle a is point a, (-1,-2)

plug in these values to the circle equation.

$())^2+())^2=5^2(x+1)^2+(y+2)^2=25$

0,0(0 оценок)

Right triangle abc is located at a (−1, −2), b (−1, 1), and c (3, 1) on a coordinate plane. what is the equation of a circle a with radius segment ac?
(x + 1)2 + (y + 2)2 = 9
(x + 1)2 + (y + 2)2 = 25
(x − 3)2 + (y − 1)2 = 16
(x − 3)2 + (y − 1)2 = 25

Ответ:

Ответ:

Ask your question to the AI advisor

More tips

Answers on questions: Mathematics

Ask an AI advisor a question