SABCD is a regular tetragonal pyramid with a base ABCD. Find the distance between BC and SD, if AB = 12, SC = 10

a) z = -2.15 has p-value = 0.0158

b) z = -0.93 has p value = 0.1762

Step-by-step explanation:

We are given two z-scores and two p-values and we have to identify which p-value belongs to which z-score without using any calculator/table.

To solve this problem we need to understand about the p-value of the z-score and what does it represent. The p-value of a z-score represents the area under the graph in a standard normal curve which is to the left of that z-score. If the z-score is increased, the area to its left will increase, so this means the p-value will also increase.

From the given z-scores, z = - 2.15 is smaller than z = - 0.93. This means the area to the left of z = - 2.15 in a standard normal curve will be lesser than that of z = - 0.93. Hence, the p-value for z = - 2.15 will be lesser than the p-value of z = - 0.93

So,

p-value for z = - 2.15 is p = 0.058

and

p-value for z = 0.1762 is p = 0.1762